(y-5)^2=2y^2-2y+32

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Solution for (y-5)^2=2y^2-2y+32 equation: 



(y-5)^2=2y^2-2y+32

We move all terms to the left:

(y-5)^2-(2y^2-2y+32)=0

We get rid of parentheses

-2y^2+(y-5)^2+2y-32=0

We add all the numbers together, and all the variables

-2y^2+2y+(y-5)^2-32=0

We move all terms containing y to the left, all other terms to the right

-2y^2+2y+(y-5)^2=32

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